①[4sin(α-π)-sin(3π/2-α)]/[3cos(α-π/2)-5cos(α-5π)] ②sin^2-2sin^2αcosα-cos^2α

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①[4sin(α-π)-sin(3π/2-α)]/[3cos(α-π/2)-5cos(α-5π)] ②sin^2-2sin^2αcosα-cos^2α
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①[4sin(α-π)-sin(3π/2-α)]/[3cos(α-π/2)-5cos(α-5π)] ②sin^2-2sin^2αcosα-cos^2α
①[4sin(α-π)-sin(3π/2-α)]/[3cos(α-π/2)-5cos(α-5π)] ②sin^2-2sin^2αcosα-cos^2α

①[4sin(α-π)-sin(3π/2-α)]/[3cos(α-π/2)-5cos(α-5π)] ②sin^2-2sin^2αcosα-cos^2α
①用换角公式
4sin(α-π)-sin(3π/2-α)=-4sina+cosa
3cos(α-π/2)-5cos(α-5π)=3sina+5cosa
同除以cosa:[-4sina+cosa]/[3sina+5cosa]
=[-4tana+1]/[3tana+5]
代入3
得到-11/14
②换成(sinθ)^2+(cosθ)^2
就得到2(sinθ)^2-2sinθcosθ+(cosθ)^2
=[2(sinθ)^2-2sinθcosθ+(cosθ)^2]/1
=[2(sinθ)^2-2sinθcosθ+(cosθ)^2]/[(sinθ)^2+(cosθ)^2]
同除以(cosθ)^2
得到[2tanθ^2-2tanθ+1]/[tanθ^2+1]
把3代入
得到13/10

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