已知cos(π/2+α)=2sin(π/2-α) 求tan(2π+α)
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已知cos(π/2+α)=2sin(π/2-α) 求tan(2π+α)
已知cos(π/2+α)=2sin(π/2-α) 求tan(2π+α)
已知cos(π/2+α)=2sin(π/2-α) 求tan(2π+α)
cos(π/2+a)=-sina
2sin(π/2-a)=2cosa 所以可得:
sina=-2cosa
即:tana=sina/cosa=-2
tan(2π+α)=tana=-2
cos(π/2+α)=-sina
2sin(π/2-α)=2cosa
cos(π/2+α)=2sin(π/2-α)
-sina=2cosa
tana=-2
tan(2π+α)=tana=-2
可以参考
cos(π/2+α)=-sina
2sin(π/2-α)=2cosa
sina=-2cosa
tan(2π+α)=tanα=sina/cosa=-2
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