( 解方程,{(x+2)²-(y+4)²=(x+y)(x-y),x-3y=-2,运用平方差
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/15 09:56:08
x)Px|i;ywFF mԨЭԩ55y)+t:"}*_`gCuW
1t+uM4m+8#tB%R16a\[J[Sj[~qAbȫ di
( 解方程,{(x+2)²-(y+4)²=(x+y)(x-y),x-3y=-2,运用平方差
( 解方程,{(x+2)²-(y+4)²=(x+y)(x-y),x-3y=-2,运用平方差
( 解方程,{(x+2)²-(y+4)²=(x+y)(x-y),x-3y=-2,运用平方差
(x+2)²-(y+4)²=(x+y)(x-y),
(x+2+y+4)(x+2-y-4)=x^2-y^2
x = 3 + 2 y
x-3y=-2
3+2y-3y=-2
3+2=y
y=5
x=3+2*5=13