数列{an}满足an+1=2an 0≤an≤1/2 an+1=2an-1 1/2≤an

数列an满足an+1=根号(an^2+1)+an,a1=a>0,求an通项公式 已知数列an满足1/a-an=2根号n,且an>0.求an的通项公式是数列{an}满足1/an-an=2根号n，且an>0，求an的通项公式。 数列{an}满足an+1=2an 0≤an≤1/2 an+1=2an-1 1/2≤an 周期性数列问题i已知数列｛an}满足a(n+1)=2an (0 已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an数列{an}满足:an>0,且根号下Sn=an+1/4,求通项an 已知数列an满足a1=1,1/an+1=根号1/an^2+2,an>0,求an 数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an 数列{an}满足:a1=1,an>0,an+1^2-an^2=1,那么an 已知数列｛an｝满足a1=1,an+1 -an+2an+1•an=0求通项 数列an满足,a1=8且8an+1an-16an+1+2an+5=0 数列{an}满足a1=a,an+1=1+1/an.若3/2 数列an满足a1=1,a(n+1)=an/[(2an)+1],求a2010 数列{an}满足a1=2,a(n+1)=2an+n+2,求an 数列[An]满足a1=2,a（n+1）=3an-2 求an 已知数列{an}满足a(n+1)=2an-an²/2,a1=1,求证an≤2且求an的通项公式 已知数列an满足a1=1/2,(an+1-1)(an-1)-an+1+an=0求数列an的通项公式 已知数列{An}满足A(n+1)=【2An (0 已知数列an满足条件a1=-2 a（n+1）=2an/(1-an) 则an=