y=1/3sin(1x/3+π/4)的图像怎么画(五点法画图)x轴的点取-π/12,π/12,π/4,5π/12,7π/12求sin(1x/3+π/4)五个对应的点是多少阿
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![y=1/3sin(1x/3+π/4)的图像怎么画(五点法画图)x轴的点取-π/12,π/12,π/4,5π/12,7π/12求sin(1x/3+π/4)五个对应的点是多少阿](/uploads/image/z/3926859-51-9.jpg?t=y%3D1%2F3sin%EF%BC%881x%2F3%2B%CF%80%2F4%EF%BC%89%E7%9A%84%E5%9B%BE%E5%83%8F%E6%80%8E%E4%B9%88%E7%94%BB%EF%BC%88%E4%BA%94%E7%82%B9%E6%B3%95%E7%94%BB%E5%9B%BE%EF%BC%89x%E8%BD%B4%E7%9A%84%E7%82%B9%E5%8F%96-%CF%80%2F12%2C%CF%80%2F12%2C%CF%80%2F4%2C5%CF%80%2F12%2C7%CF%80%2F12%E6%B1%82sin%EF%BC%881x%2F3%2B%CF%80%2F4%EF%BC%89%E4%BA%94%E4%B8%AA%E5%AF%B9%E5%BA%94%E7%9A%84%E7%82%B9%E6%98%AF%E5%A4%9A%E5%B0%91%E9%98%BF)
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y=1/3sin(1x/3+π/4)的图像怎么画(五点法画图)x轴的点取-π/12,π/12,π/4,5π/12,7π/12求sin(1x/3+π/4)五个对应的点是多少阿
y=1/3sin(1x/3+π/4)的图像怎么画(五点法画图)
x轴的点取-π/12,π/12,π/4,5π/12,7π/12
求sin(1x/3+π/4)五个对应的点是多少阿
y=1/3sin(1x/3+π/4)的图像怎么画(五点法画图)x轴的点取-π/12,π/12,π/4,5π/12,7π/12求sin(1x/3+π/4)五个对应的点是多少阿
五点法是对sinX内的整体值X而言的,
就是不管sin( )内的具体角是什么,都统一把( )内的角设成X.
并令X=0,π/2,π,3π/2,2π;
也就是1x/3+π/4分别=0,π/2,π,3π/2,2π时,解出其中的x即可.
这样,其x的取值就是:-π/12,π/12,π/4,5π/12,7π/12