如图,在△ABC中,∠C=90°AD是∠BAC的平分线,DE⊥AB于E,点F在AB上,BD⊥DF.求证:CD=DE CF=EB(顺便问一句:其中BD⊥DF是不是我抄错了?按对的做!)
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![如图,在△ABC中,∠C=90°AD是∠BAC的平分线,DE⊥AB于E,点F在AB上,BD⊥DF.求证:CD=DE CF=EB(顺便问一句:其中BD⊥DF是不是我抄错了?按对的做!)](/uploads/image/z/3927677-5-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E2%88%A0C%3D90%C2%B0AD%E6%98%AF%E2%88%A0BAC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%2CDE%E2%8A%A5AB%E4%BA%8EE%2C%E7%82%B9F%E5%9C%A8AB%E4%B8%8A%2CBD%E2%8A%A5DF.%E6%B1%82%E8%AF%81%EF%BC%9ACD%3DDE++++++++++CF%3DEB%28%E9%A1%BA%E4%BE%BF%E9%97%AE%E4%B8%80%E5%8F%A5%EF%BC%9A%E5%85%B6%E4%B8%ADBD%E2%8A%A5DF%E6%98%AF%E4%B8%8D%E6%98%AF%E6%88%91%E6%8A%84%E9%94%99%E4%BA%86%3F%E6%8C%89%E5%AF%B9%E7%9A%84%E5%81%9A%21%29)
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