一道数学化简题,若x-y\x+y=1\2,求x-y\x+y-2(x+y)\x-y的值(注:不会打分数,\左边是分子,\右边是分母,一定要有简化过程)
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![一道数学化简题,若x-y\x+y=1\2,求x-y\x+y-2(x+y)\x-y的值(注:不会打分数,\左边是分子,\右边是分母,一定要有简化过程)](/uploads/image/z/3931795-19-5.jpg?t=%E4%B8%80%E9%81%93%E6%95%B0%E5%AD%A6%E5%8C%96%E7%AE%80%E9%A2%98%2C%E8%8B%A5x-y%5Cx%2By%3D1%5C2%2C%E6%B1%82x-y%5Cx%2By-2%28x%2By%29%5Cx-y%E7%9A%84%E5%80%BC%EF%BC%88%E6%B3%A8%EF%BC%9A%E4%B8%8D%E4%BC%9A%E6%89%93%E5%88%86%E6%95%B0%2C%5C%E5%B7%A6%E8%BE%B9%E6%98%AF%E5%88%86%E5%AD%90%2C%5C%E5%8F%B3%E8%BE%B9%E6%98%AF%E5%88%86%E6%AF%8D%2C%E4%B8%80%E5%AE%9A%E8%A6%81%E6%9C%89%E7%AE%80%E5%8C%96%E8%BF%87%E7%A8%8B%EF%BC%89)
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一道数学化简题,若x-y\x+y=1\2,求x-y\x+y-2(x+y)\x-y的值(注:不会打分数,\左边是分子,\右边是分母,一定要有简化过程)
一道数学化简题,
若x-y\x+y=1\2,求x-y\x+y-2(x+y)\x-y的值
(注:不会打分数,\左边是分子,\右边是分母,一定要有简化过程)
一道数学化简题,若x-y\x+y=1\2,求x-y\x+y-2(x+y)\x-y的值(注:不会打分数,\左边是分子,\右边是分母,一定要有简化过程)
x-y\x+y=1\2 所以(x+y)\x-y是x-y\x+y的倒数=2 所以原式=1\2-2*2=-7/2