sin(π/3+α)=1/3,则cos(π/6-α)=

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sin(π/3+α)=1/3,则cos(π/6-α)=
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sin(π/3+α)=1/3,则cos(π/6-α)=
sin(π/3+α)=1/3,则cos(π/6-α)=

sin(π/3+α)=1/3,则cos(π/6-α)=
根据诱导公式:sin(π/2-α)=cosα
得:
cos(π/6-α)
=sin[π/2-(π/6-α)]
=sin(π/3+α)
=1/3