先化简再求值(a+b)^2-(a+b)(a-2b)-(ab^2+2/3b^3) ÷1/3b a=-2013 b=-1

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/26 01:23:05
先化简再求值(a+b)^2-(a+b)(a-2b)-(ab^2+2/3b^3) ÷1/3b a=-2013 b=-1
x=0 Q cңD*@b(0 X`)gIbP/yNώ, TvmK[5IjƁS Ђ=GEb| `wee!%[ʸ})3Qr3`n3v(ͬH2D4i"?O5;F`E~zqz7W{6{;}|

先化简再求值(a+b)^2-(a+b)(a-2b)-(ab^2+2/3b^3) ÷1/3b a=-2013 b=-1
先化简再求值(a+b)^2-(a+b)(a-2b)-(ab^2+2/3b^3) ÷1/3b a=-2013 b=-1

先化简再求值(a+b)^2-(a+b)(a-2b)-(ab^2+2/3b^3) ÷1/3b a=-2013 b=-1
(a+b)^2-(a+b)(a-2b)-(ab^2+2/3b^3) ÷1/3b
=a^2+2ab+b^2-a^2+ab+2b^2-3ab-2/b^4
=3b^2-2/b^4
=3-2
=1

(a+b)^2-(a+b)(a-2b)-(ab^2+2/3b^3) ÷1/3b
=a^+2ab+b^-(a^-ab-2b^)-(3ab+2b^)
=a^+2ab+b^
-a^+ab+2b^
-3ab-2b^
= b^,
当a=-2013, b=-1时原式=1.