已知:如图所示,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,且点B,A,D在一条直线上,连接BE,CD,M,N分别为BE,CD的中点.求证:①BE=CD;②△AMN是等腰三角形.
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/27 03:35:39
![已知:如图所示,在△ABC和△ADE中,AB=AC,AD=AE,∠BAC=∠DAE,且点B,A,D在一条直线上,连接BE,CD,M,N分别为BE,CD的中点.求证:①BE=CD;②△AMN是等腰三角形.](/uploads/image/z/3957556-4-6.jpg?t=%E5%B7%B2%E7%9F%A5%EF%BC%9A%E5%A6%82%E5%9B%BE%E6%89%80%E7%A4%BA%2C%E5%9C%A8%E2%96%B3ABC%E5%92%8C%E2%96%B3ADE%E4%B8%AD%2CAB%3DAC%2CAD%3DAE%2C%E2%88%A0BAC%3D%E2%88%A0DAE%2C%E4%B8%94%E7%82%B9B%2CA%2CD%E5%9C%A8%E4%B8%80%E6%9D%A1%E7%9B%B4%E7%BA%BF%E4%B8%8A%2C%E8%BF%9E%E6%8E%A5BE%2CCD%2CM%2CN%E5%88%86%E5%88%AB%E4%B8%BABE%2CCD%E7%9A%84%E4%B8%AD%E7%82%B9.%E6%B1%82%E8%AF%81%EF%BC%9A%E2%91%A0BE%3DCD%EF%BC%9B%E2%91%A1%E2%96%B3AMN%E6%98%AF%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2.)
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