(ab+1)²-(a+b)² 因式分解如题~
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(ab+1)²-(a+b)² 因式分解如题~
(ab+1)²-(a+b)² 因式分解
如题~
(ab+1)²-(a+b)² 因式分解如题~
(ab+1)²-(a+b)²
=(ab+1-a-b)(ab+1+a+b)
=[a(b-1)-(b-1)][a(b+1)+(b+1)]
=(b-1)(a-1)(b+1)(a+1)
(ab+1)^2-(a+b)^2
=(ab+1-a-b)(ab+1+a+b)
=[a(b-1)-(b-1)][a(b+1)+(b+1)]
=(b-1)(a-1)(b+1)(a+1)
=(ab+1+a+b)(ab+1-a-b)=[a(b+1)+(b+1)][a(b-1)-(b-1)]
=(a+1)(b+1)(a-1)(b-1)
=[(ab+1)+(a+b)][(ab+1)-(a+b)]
=(ab+1+a+b)(ab+1-a-b)
=(a+1)(b+1)(a-1)(b-1)