(x+1)²-3(X+1)+12=0还有 y\4-y²=1
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(x+1)²-3(X+1)+12=0还有 y\4-y²=1
(x+1)²-3(X+1)+12=0
还有 y\4-y²=1
(x+1)²-3(X+1)+12=0还有 y\4-y²=1
(x+1)²-3(X+1)+12
=[(x+1)-3/2]²+39/4>0
方程无实数解
(x+1)²-3(X+1)+12=0
x²+2x+1-3x-3+12=0
x²-x+8=0
△=(-1)²-4×8=-31<0
∴原方程无实数解
y/4-y²=1
y-4y²=4
-4y²+y-4=0
4y²-y+4=0
△=(-1)²-4×4×4=1-64=-63<0
∴原方程无实数解