解方程题(1+√2)x²-(3+√2)x+√2=0
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解方程题(1+√2)x²-(3+√2)x+√2=0
解方程题
(1+√2)x²-(3+√2)x+√2=0
解方程题(1+√2)x²-(3+√2)x+√2=0
(1+√2)x²-(3+√2)x+√2=0
十字相乘得:
[(1+√2)x-1](x-√2)=0
x1=√2-1,x2=√2
1+√2 -1
×
1 -√2
x系数是-√2-2-1=-(3+√2)
所以[(1+√2)x-1](x-√2)=0
所以x=√2-1,x=√2