分解因式:3x²+5xy-2y²﹢x﹢9y-4
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/06 02:28:35
xTJ@~ 붤`y )zٽJZ*=hUڐM)`I%^
dfBrI4N;2Qhn8䖅ai%s7&Yc+2C :CE5\ HXUIkf.D*;^o<\'0(Q
7W! QQ1==FUftWkuzOxt5N]г;jjF_zJΪ)R-!rY[r̭?xkLC\RKwj`,υӑ""QH=Z$DwD!|m`j>TN,
分解因式:3x²+5xy-2y²﹢x﹢9y-4
分解因式:3x²+5xy-2y²﹢x﹢9y-4
分解因式:3x²+5xy-2y²﹢x﹢9y-4
3x²+5xy-2y²﹢x﹢9y-4
=(3x-y)(x+2y)+x+9y-4
=(3x-y)(x+2y)+4x+8y-3x+y-4
=(3x-y)(x+2y)+4(x+2y)-(3x-y)-4
=(3x-y+4)(x+2y-1)
原式=(3x-y)(x+2y)+x+9y-4
十字相乘
3x-y 4
×
x+2y -1
x系数-3+4=1
y系数1+8=9
符合
所以原式=(3x-y+4)(x+2y-1)
=(3x-y)(x+2y)+x+9y-4
=(3x-y+4)(x+2y-1)
3x²+5xy-2y²+x+9y-4
用待定系数法做
因为3x²+5xy-2y²=(3x-y)(x+2y)
所以设3x²+5xy-2y²+x+9y-4=(3x-y+a)(x+2y+b)
=3x²+5xy-2y²+ax+2ay+3bx-by+ab
=3x²+5xy-2y&...
全部展开
3x²+5xy-2y²+x+9y-4
用待定系数法做
因为3x²+5xy-2y²=(3x-y)(x+2y)
所以设3x²+5xy-2y²+x+9y-4=(3x-y+a)(x+2y+b)
=3x²+5xy-2y²+ax+2ay+3bx-by+ab
=3x²+5xy-2y²+(a+3b)x+(2a-b)y+ab
比较系数,得 a+3b=1, 2a-b=9, ab=-4
解得 a=4,b=-1
所以3x²+5xy-2y²+x+9y-4=(3x-y+4)(x+2y-1)
收起