|x+y+4|+(x-2)²=0则3z+2y=

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|x+y+4|+(x-2)²=0则3z+2y=
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|x+y+4|+(x-2)²=0则3z+2y=
|x+y+4|+(x-2)²=0则3z+2y=

|x+y+4|+(x-2)²=0则3z+2y=
|x+y+4|+(x-2)²=0
则:
x+y+4=0
x-2=0
解得:
x=2;y=-6
3x+2y=6-12=-6

|x+y+4|+(x-2)²=0
则x+y=-4 x=2
∴y=-6
∴3x+2y=6-12=-6

因为绝对值和平方都是正数,所以x+y=-4,x=2