已知f(x)=﹛(x-1)²,(x>0) f(x+1)+1,(x≦0)则f(1)+f(-1)的值为已知f(x)=﹛(x-1)²,(x>0)f(x+1)+1,(x≦0)则f(1)+f(-1)的值为
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![已知f(x)=﹛(x-1)²,(x>0) f(x+1)+1,(x≦0)则f(1)+f(-1)的值为已知f(x)=﹛(x-1)²,(x>0)f(x+1)+1,(x≦0)则f(1)+f(-1)的值为](/uploads/image/z/3985714-10-4.jpg?t=%E5%B7%B2%E7%9F%A5f%EF%BC%88x%EF%BC%89%3D%EF%B9%9B%EF%BC%88x-1%EF%BC%89%26%23178%3B%2C%28x%EF%BC%9E0%EF%BC%89+f%EF%BC%88x%2B1%EF%BC%89%2B1%2C%EF%BC%88x%E2%89%A60%EF%BC%89%E5%88%99f%EF%BC%881%EF%BC%89%2Bf%EF%BC%88-1%EF%BC%89%E7%9A%84%E5%80%BC%E4%B8%BA%E5%B7%B2%E7%9F%A5f%EF%BC%88x%EF%BC%89%3D%EF%B9%9B%EF%BC%88x-1%EF%BC%89%26%23178%3B%2C%28x%EF%BC%9E0%EF%BC%89f%EF%BC%88x%2B1%EF%BC%89%2B1%2C%EF%BC%88x%E2%89%A60%EF%BC%89%E5%88%99f%EF%BC%881%EF%BC%89%2Bf%EF%BC%88-1%EF%BC%89%E7%9A%84%E5%80%BC%E4%B8%BA)
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已知f(x)=﹛(x-1)²,(x>0) f(x+1)+1,(x≦0)则f(1)+f(-1)的值为已知f(x)=﹛(x-1)²,(x>0)f(x+1)+1,(x≦0)则f(1)+f(-1)的值为
已知f(x)=﹛(x-1)²,(x>0) f(x+1)+1,(x≦0)则f(1)+f(-1)的值为
已知f(x)=﹛(x-1)²,(x>0)
f(x+1)+1,(x≦0)则f(1)+f(-1)的值为
已知f(x)=﹛(x-1)²,(x>0) f(x+1)+1,(x≦0)则f(1)+f(-1)的值为已知f(x)=﹛(x-1)²,(x>0)f(x+1)+1,(x≦0)则f(1)+f(-1)的值为
1>0 f(1)=(1-1)²=0
-1
解:
f(1)+f(-1)
=0+f(0)+1
=f(1)+1+1
=0+1+1
=2
答:……