如图在△ABC中,AB=AC,D为AB上一点,E为AC延长线上的一点,且CE=BD,连接DE交BC于点P,求证PD=PE.
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![如图在△ABC中,AB=AC,D为AB上一点,E为AC延长线上的一点,且CE=BD,连接DE交BC于点P,求证PD=PE.](/uploads/image/z/3989752-16-2.jpg?t=%E5%A6%82%E5%9B%BE%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAB%3DAC%2CD%E4%B8%BAAB%E4%B8%8A%E4%B8%80%E7%82%B9%2CE%E4%B8%BAAC%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%B8%8A%E7%9A%84%E4%B8%80%E7%82%B9%2C%E4%B8%94CE%3DBD%2C%E8%BF%9E%E6%8E%A5DE%E4%BA%A4BC%E4%BA%8E%E7%82%B9P%2C%E6%B1%82%E8%AF%81PD%3DPE.)
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