#include int fun(int*x,int n) { if (n==0) return x[0]; else return x[0]+fun(x+1,n-1); }void main(){int a[]={1,2,3,4,5,6,7};printf("%d\n",fun(a,2) );}
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#include int fun(int*x,int n) { if (n==0) return x[0]; else return x[0]+fun(x+1,n-1); }void main(){int a[]={1,2,3,4,5,6,7};printf("%d\n",fun(a,2) );}
#include int fun(int*x,int n) { if (n==0) return x[0]; else return x[0]+fun(x+1,n-1); }
void main()
{
int a[]={1,2,3,4,5,6,7};
printf("%d\n",fun(a,2) );
}
#include int fun(int*x,int n) { if (n==0) return x[0]; else return x[0]+fun(x+1,n-1); }void main(){int a[]={1,2,3,4,5,6,7};printf("%d\n",fun(a,2) );}
#include
int fun(int*x,int n)
{
if (n==0)
return x[0];
else
return x[0]+fun(x+1,n-1);
}
如果n = 0,那么返回 数组 x的第一个元素,如果 n !=0 那么后面将会是一个递归算法.
请把代码贴完,还有你想说明的是什么?想问什么?
#include stdio.h double fun(int m) { // }
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,m);}
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下面的这个是参考答案上的程序# include void fun(int (*str)[10],int *a,int *n,int mm,int nn){int i,j;for(j=0;j
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');}
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#include sub(int *a,int n,int k) { if(k