已知﹙a+2²﹚+﹙3b-1﹚=0求 3a²-[2ab²-6﹙ab- 1/2 a²b﹚-2ab的值
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已知﹙a+2²﹚+﹙3b-1﹚=0求 3a²-[2ab²-6﹙ab- 1/2 a²b﹚-2ab的值
已知﹙a+2²﹚+﹙3b-1﹚=0求 3a²-[2ab²-6﹙ab- 1/2 a²b﹚-2ab的值
已知﹙a+2²﹚+﹙3b-1﹚=0求 3a²-[2ab²-6﹙ab- 1/2 a²b﹚-2ab的值
是﹙a+2)²+|3b-1|=0
所以a-2=0,3b-1=0
a=2,b=1/3
所以原式=3a²-2ab²+6﹙ab- 1/2 a²b﹚+2ab
=3a²-2ab²+6ab-3a²b+2ab
=3a²-2ab²+8ab-3a²b
=12-4/9+16/3-4
=116/9