已知x+y+z=π,证明sin(x+y)+sin(y+z)+sin(z+x)≥sin2x+sin2y+sin2z

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/19 08:51:49
已知x+y+z=π,证明sin(x+y)+sin(y+z)+sin(z+x)≥sin2x+sin2y+sin2z
x){}K++l7XlF_qfPHS@U:F J0YeTOs l';z|i'Ov3 ,iomgb i $c55*<$=F0w&kTQ[傜 BubhBՃٌ}[<[?ˀ|~<;PxX

已知x+y+z=π,证明sin(x+y)+sin(y+z)+sin(z+x)≥sin2x+sin2y+sin2z
已知x+y+z=π,证明sin(x+y)+sin(y+z)+sin(z+x)≥sin2x+sin2y+sin2z

已知x+y+z=π,证明sin(x+y)+sin(y+z)+sin(z+x)≥sin2x+sin2y+sin2z
不等式右侧等于:
1/2[2sin2x+2sin2y+2sin2z]
=1/2[(sin2x+sin2y)+(sin2y+sin2z)+(sin2x+sin2z)]
=1/2[2sin(x+y)cos(x-y)+2sin(y+z)(y-z)+2sin(z+x)(y-z)]
=sin(x+y)cos(x-y)+sin(y+z)(y-z)+sin(z+x)(y-z)
显然,比不等式左侧要小