分解因式:[(x-1)+(y-xy)]²怎样变成[(x-1)*(1-y)]²
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分解因式:[(x-1)+(y-xy)]²怎样变成[(x-1)*(1-y)]²
分解因式:[(x-1)+(y-xy)]²怎样变成[(x-1)*(1-y)]²
分解因式:[(x-1)+(y-xy)]²怎样变成[(x-1)*(1-y)]²
[ (x - 1) + (y - xy) ]"
= [ (x - 1) - (xy - y) ]"
= [ (x - 1) - y(x - 1) ]"
= [ (x - 1)(1 - y) ]"
(x-1)+(y-xy)
=(x-1)+y(1-x)
=(x-1)-y(x-1)
=(x-1)(1-y)
原式=[(x-1)-y(x-1)]²
=[(x-1)(1-y)]²
[ (x - 1) + (y - xy) ]"= [ (x - 1) - (xy - y) ]"= [ (x - 1) - y(x - 1) ]"= [ (x - 1)(1 - y) ]" 就到这里,,
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