(1) 若f(x)是偶函数,g(x)是奇函数,且f(x)+g(x)=x²+x-2,求f(x)和g(x)的解析式(2)设f(x)=以1/2为底(1-ax)/x-1的对数:①求a的值 ②证明:f(x)在区间(1,+∞)为单调递增
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![(1) 若f(x)是偶函数,g(x)是奇函数,且f(x)+g(x)=x²+x-2,求f(x)和g(x)的解析式(2)设f(x)=以1/2为底(1-ax)/x-1的对数:①求a的值 ②证明:f(x)在区间(1,+∞)为单调递增](/uploads/image/z/3998453-5-3.jpg?t=%EF%BC%881%EF%BC%89+%E8%8B%A5f%28x%29%E6%98%AF%E5%81%B6%E5%87%BD%E6%95%B0%2Cg%28x%29%E6%98%AF%E5%A5%87%E5%87%BD%E6%95%B0%2C%E4%B8%94f%28x%29%2Bg%28x%29%3Dx%26sup2%3B%2Bx-2%2C%E6%B1%82f%EF%BC%88x%EF%BC%89%E5%92%8Cg%EF%BC%88x%EF%BC%89%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F%EF%BC%882%EF%BC%89%E8%AE%BEf%28x%29%3D%E4%BB%A51%2F2%E4%B8%BA%E5%BA%95%EF%BC%881-ax%EF%BC%89%2Fx-1%E7%9A%84%E5%AF%B9%E6%95%B0%EF%BC%9A%E2%91%A0%E6%B1%82a%E7%9A%84%E5%80%BC+%E2%91%A1%E8%AF%81%E6%98%8E%EF%BC%9Af%28x%29%E5%9C%A8%E5%8C%BA%E9%97%B4%EF%BC%881%2C%2B%E2%88%9E%EF%BC%89%E4%B8%BA%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E)
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(1) 若f(x)是偶函数,g(x)是奇函数,且f(x)+g(x)=x²+x-2,求f(x)和g(x)的解析式(2)设f(x)=以1/2为底(1-ax)/x-1的对数:①求a的值 ②证明:f(x)在区间(1,+∞)为单调递增
(1) 若f(x)是偶函数,g(x)是奇函数,且f(x)+g(x)=x²+x-2,求f(x)和g(x)的解析式
(2)设f(x)=以1/2为底(1-ax)/x-1的对数:①求a的值 ②证明:f(x)在区间(1,+∞)为单调递增
(1) 若f(x)是偶函数,g(x)是奇函数,且f(x)+g(x)=x²+x-2,求f(x)和g(x)的解析式(2)设f(x)=以1/2为底(1-ax)/x-1的对数:①求a的值 ②证明:f(x)在区间(1,+∞)为单调递增
f(x)是偶函数→f(x)=f(-x)
g(x)是奇函数g(x)=-g(-x)
f(x)+g(x)=x²+x-2 ...①
f(-x)+g(-x)=(-x)²-x-2...②
①-②的g(x)-g(-x)=2x
2g(x)=2x
g(x)=x
所以f(x)=x²+x-2-g(x)=x²-2
(有什么不懂发信息来)