已知Iab-2I与Ib-1I互为相反数,试求式子:1/ab + 1/(a+1)(b+1) + 1/(a+2)(b+2) +.+ 1/(a+2009)(b+2009)的值.

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已知Iab-2I与Ib-1I互为相反数,试求式子:1/ab + 1/(a+1)(b+1) + 1/(a+2)(b+2) +.+ 1/(a+2009)(b+2009)的值.
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已知Iab-2I与Ib-1I互为相反数,试求式子:1/ab + 1/(a+1)(b+1) + 1/(a+2)(b+2) +.+ 1/(a+2009)(b+2009)的值.
已知Iab-2I与Ib-1I互为相反数,试求式子:
1/ab + 1/(a+1)(b+1) + 1/(a+2)(b+2) +.+ 1/(a+2009)(b+2009)的值.

已知Iab-2I与Ib-1I互为相反数,试求式子:1/ab + 1/(a+1)(b+1) + 1/(a+2)(b+2) +.+ 1/(a+2009)(b+2009)的值.
因为Iab-2I与Ib-1I互为相反数,Iab-2I与Ib-1I都大于等于0,所以Iab-2I=Ib-1I=0,所以a=2,b=1
所以原式子为1/(1*2)+1/(2*3)+1/(3*4)+.+1/(2011*2010)=1/1-1/2+1/2-1/3+1/3-1/4 +.+1/2010-1/2011=1-1/2011=2010/2011
注:1/2=1/1-1/2,1/(2*3)=1/2-1/3,1/(3*4)=1/3-1/4.

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