当a取什么值时,方程(x-1/x-2)-(x-2/x+1)=2x+a/(x-2)(x+1)有增根
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当a取什么值时,方程(x-1/x-2)-(x-2/x+1)=2x+a/(x-2)(x+1)有增根
当a取什么值时,方程(x-1/x-2)-(x-2/x+1)=2x+a/(x-2)(x+1)有增根
当a取什么值时,方程(x-1/x-2)-(x-2/x+1)=2x+a/(x-2)(x+1)有增根
(x-1)/(x-2)-(x-2)/(x+1)=(2x+a)/[(x-2)(x+1)]
(x-1)/(x-2)-(x-2)/(x+1)-(2x+a)/[(x-2)(x+1)] = 0
[(x-1)(x+1)-(x-2)²-(2x+a)] / [(x-2)(x+1)] = 0
[(x²-1)-(x²-4x+4)-(2x+a)] / [(x-2)(x+1)] = 0
[x²-1-x²+4x-4-2x-a] / [(x-2)(x+1)] = 0
2[x-(a+5)/2] / [(x-2)(x+1)] = 0
当x-(a+5)/2 = x-2,或x-(a+5)/2 = x+1,即当a=-1,或a=-7时有增根
(x-1/x-2)-(x-2/x+1)=2x+a/(x-2)(x+1)
同乘以(x-2)(x+1)得
x²-1-(x-2)²=2x+a
4x-5=2x+a
2x=a+5
有增根,即分母=0时,x=-1或2
此时:
①x=-1,-2=a+5,a=-7
②x=2,4=a+5,a=-1如果无解或有解呢a=-1或-7时方程...
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(x-1/x-2)-(x-2/x+1)=2x+a/(x-2)(x+1)
同乘以(x-2)(x+1)得
x²-1-(x-2)²=2x+a
4x-5=2x+a
2x=a+5
有增根,即分母=0时,x=-1或2
此时:
①x=-1,-2=a+5,a=-7
②x=2,4=a+5,a=-1
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