设数列{an}满足a(1)=1,a(n+1)=a(n)+2^n,b∈N* (1)求数列{a(n)}的通项公式; (2)令b(n)=n*a(n),求数列{b(n)}的前n项和T(n).
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![设数列{an}满足a(1)=1,a(n+1)=a(n)+2^n,b∈N* (1)求数列{a(n)}的通项公式; (2)令b(n)=n*a(n),求数列{b(n)}的前n项和T(n).](/uploads/image/z/400419-27-9.jpg?t=%E8%AE%BE%E6%95%B0%E5%88%97%7Ban%7D%E6%BB%A1%E8%B6%B3a%EF%BC%881%EF%BC%89%3D1%2Ca%EF%BC%88n%2B1%EF%BC%89%3Da%EF%BC%88n%EF%BC%89%2B2%5En%2Cb%E2%88%88N%2A+%281%29%E6%B1%82%E6%95%B0%E5%88%97%7Ba%EF%BC%88n%EF%BC%89%7D%E7%9A%84%E9%80%9A%E9%A1%B9%E5%85%AC%E5%BC%8F%EF%BC%9B+%282%29%E4%BB%A4b%EF%BC%88n%EF%BC%89%3Dn%2Aa%EF%BC%88n%EF%BC%89%2C%E6%B1%82%E6%95%B0%E5%88%97%EF%BD%9Bb%EF%BC%88n%EF%BC%89%EF%BD%9D%E7%9A%84%E5%89%8Dn%E9%A1%B9%E5%92%8CT%EF%BC%88n%EF%BC%89.)
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