通分1/x-1,1/x^2-1,1/x^2+x

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通分1/x-1,1/x^2-1,1/x^2+x
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通分1/x-1,1/x^2-1,1/x^2+x
通分1/x-1,1/x^2-1,1/x^2+x

通分1/x-1,1/x^2-1,1/x^2+x
公分母为:x(x+1)(x-1)
1/(x-1)=[x(x+1)]/[x(x+1)(x-1)]
1/(x²-1)=x//[x(x+1)(x-1)]
1/(x²+x)=(x-1)/[x(x+1)(x-1)]

答:
1/(x-1)
1/(x^2-1)=1/[(x-1)(x+1)]
1/(x^2+x)=1/[x(x+1)]
所以:通分后的分母为x(x-1)(x+1)
所以:通分后为:
(x^2+x) / [x(x-1)(x+1)]
x / [x(x-1)(x+1)]
(x-1) / [x(x-1)(x+1)]