如图,在等腰三角形ABC中,AB=AC,D是BC边上一动点,DE⊥AB,DF⊥ACE,F为垂足,若DE+DF=2√2,S△ABC=3√2+2√6.你能求出AB的长吗?
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![如图,在等腰三角形ABC中,AB=AC,D是BC边上一动点,DE⊥AB,DF⊥ACE,F为垂足,若DE+DF=2√2,S△ABC=3√2+2√6.你能求出AB的长吗?](/uploads/image/z/4015294-70-4.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E7%AD%89%E8%85%B0%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2CAB%3DAC%2CD%E6%98%AFBC%E8%BE%B9%E4%B8%8A%E4%B8%80%E5%8A%A8%E7%82%B9%2CDE%E2%8A%A5AB%2CDF%E2%8A%A5ACE%2CF%E4%B8%BA%E5%9E%82%E8%B6%B3%2C%E8%8B%A5DE%2BDF%3D2%E2%88%9A2%2CS%E2%96%B3ABC%3D3%E2%88%9A2%2B2%E2%88%9A6.%E4%BD%A0%E8%83%BD%E6%B1%82%E5%87%BAAB%E7%9A%84%E9%95%BF%E5%90%97%3F)
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