2sin^2 a·cos^2 a=(1/2)sin^2 a怎么变来的?

求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a 求证:sin 2a/1+sin a+cos a=sin a+cos a-1急 证明Cos^A-Sin^A=1-2Sin^A=2Cos^A-1=cos^a-sin^a 求证 1+sin a+cos a+2sin a*cos a/1 +sin a +cos a = sin a+ cos a 有什么思路! sin 2a+2sin方a/ 1+tan a =2sin a cos a tan a/2=sin/1+cos a=1-cos a/sin a 求证：tan a/2＝(1-cos)/sin a=sin a/(cos a+1) sin a/(1+cos a)=1/2,求sin a+cos a 已知 sin a-cos a=1/2,则 sin^3 a-cos^3 a 证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2证明 sin^2A+sin^2B-sin^2A*sin^2B+cos^2A*cos^2B=1 化简(1-sin^6 a-cos^6 a)/(cos^2 a-cos^4 a)== 已知sin a+cos a= -1/5 求1）sin acos a 2）sin a-cos a cosA+cos^2A=1,sin^2A+sin^4A+sin^8A 由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证：1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a) sin^4+sin^2cos^2+cos^2a= 一个简单的三角函数题(sin a + cos a)/(sin a - cos a) 则 sin a *cos a=(sin a + cos a)/(sin a - cos a) = 2 则 sin a *cos a= 2sin^2 a·cos^2 a=(1/2)sin^2 a sin^2(a+pai)-cos(pai+a)*cos(-a)+1