[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]=?

来源：学生作业帮助网编辑：作业帮时间：2024/11/30 07:25:53

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[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]=?
[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]=?

[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]=?
[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]
=[sin(45°+θ)]/[sin(45°+θ)]-[sin(θ+30°)]/[sin(θ+30°)]
=1-1
=0

这个问题你到三角函数的积化和差、积差化积的公式上面看看，应该就可以弄出来了，

[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]
=[cos(90°-(45°+θ))]/[cos(45°-θ)]-[sin(90°-(θ+60°))]/[sin(θ+30°)]
=cos(45°-θ)/cos(45°-θ)-sin(30°-θ)/sin(θ+30°)
=1-sin(30°-θ)/sin(θ+30°)
题有没有错

化简 sin(θ+75°)+cos(θ+45°)+cos(θ+15°)化简题sin(θ+75°)+cos(θ+45°)+cos(θ+15°) [sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]=? 求值：sin(θ+75°)+cos(θ+45°)-√3cos(θ+15°) 求值：sin(θ+75°)+cos(θ+45°)-√3cos(θ+15°) 已知θ为正锐角,求证sinθ+cosθsinθ+cosθ=根号2倍的sin(θ+45°）己知sin^2θ=sinα cosα 求cos2θ=2sin(45°-α) cos(45°+α) 急!~~ sin(a+45°)sin(a+15°)+cos(a+45°)cos(a+15°) 求sin(θ+75°)+cos(θ+45°)-√3×cos(θ+15°)的值求sin(θ+75°)+cos(θ+45°)-√3cos(θ+15°)的值. cos²45°/sin²45°-tan45° 化解cos(45°-a)-sin(45°+a) Sin^2 45°+cos^2 45°=? -cos(α-45°)=sin(α+45°)对吗? 化简cos(45°-α)-sin(45°+α),得 cos 60°+sin 45°-tan 30°=? cos tan sin 30° 45° 60°是多少 sin ²45° +cos²30° sin和cos的 45° 各是多少?帮个忙了