sin25π/6 + cos25π/3 + tan(-25π/4)这题怎么算?

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sin25π/6 + cos25π/3 + tan(-25π/4)这题怎么算?
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sin25π/6 + cos25π/3 + tan(-25π/4)这题怎么算?
sin25π/6 + cos25π/3 + tan(-25π/4)
这题怎么算?

sin25π/6 + cos25π/3 + tan(-25π/4)这题怎么算?
sin25π/6 + cos25π/3 + tan(-25π/4)=sin(4π+π/6)+cos(8π+π/3)-tan(6π+π/4)=sinπ/6+cosπ/3-tanπ/4=1/2+1/2-1=0
楼主基础知识不牢靠啊!好好把公式记记哦