各位大神们,我在用matlab解一个高次方程时出了问题.它只给我返回了一个虚根.clcclearsyms hc1E0=7.1260;q=11;fai=0.9030;g=9.8;A=3.76;f=(hc1+(q^2)/(2*g*(fai^2)*hc1^2))-E0-((1.05*(hc1/2)*(sqrt(1+8*((q^2)/(g*hc1^3)))-1))+(q^2)/(2
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/03 15:33:42
![各位大神们,我在用matlab解一个高次方程时出了问题.它只给我返回了一个虚根.clcclearsyms hc1E0=7.1260;q=11;fai=0.9030;g=9.8;A=3.76;f=(hc1+(q^2)/(2*g*(fai^2)*hc1^2))-E0-((1.05*(hc1/2)*(sqrt(1+8*((q^2)/(g*hc1^3)))-1))+(q^2)/(2](/uploads/image/z/4028815-55-5.jpg?t=%E5%90%84%E4%BD%8D%E5%A4%A7%E7%A5%9E%E4%BB%AC%2C%E6%88%91%E5%9C%A8%E7%94%A8matlab%E8%A7%A3%E4%B8%80%E4%B8%AA%E9%AB%98%E6%AC%A1%E6%96%B9%E7%A8%8B%E6%97%B6%E5%87%BA%E4%BA%86%E9%97%AE%E9%A2%98.%E5%AE%83%E5%8F%AA%E7%BB%99%E6%88%91%E8%BF%94%E5%9B%9E%E4%BA%86%E4%B8%80%E4%B8%AA%E8%99%9A%E6%A0%B9.clcclearsyms+hc1E0%3D7.1260%3Bq%3D11%3Bfai%3D0.9030%3Bg%3D9.8%3BA%3D3.76%3Bf%3D%28hc1%2B%28q%5E2%29%2F%282%2Ag%2A%28fai%5E2%29%2Ahc1%5E2%29%29-E0-%28%281.05%2A%28hc1%2F2%29%2A%28sqrt%281%2B8%2A%28%28q%5E2%29%2F%28g%2Ahc1%5E3%29%29%29-1%29%29%2B%28q%5E2%29%2F%282)
各位大神们,我在用matlab解一个高次方程时出了问题.它只给我返回了一个虚根.clcclearsyms hc1E0=7.1260;q=11;fai=0.9030;g=9.8;A=3.76;f=(hc1+(q^2)/(2*g*(fai^2)*hc1^2))-E0-((1.05*(hc1/2)*(sqrt(1+8*((q^2)/(g*hc1^3)))-1))+(q^2)/(2
各位大神们,我在用matlab解一个高次方程时出了问题.它只给我返回了一个虚根.
clc
clear
syms hc1
E0=7.1260;
q=11;
fai=0.9030;
g=9.8;
A=3.76;
f=(hc1+(q^2)/(2*g*(fai^2)*hc1^2))-E0-((1.05*(hc1/2)*(sqrt(1+8*((q^2)/(g*hc1^3)))-1))+(q^2)/(2*g*(1.05*(hc1/2)*(sqrt(1+8*((q^2)/(g*hc1^3)))-1))^2)-A)
hc0=solve(f)
事实上我在用maple求解后发现它有七个根,包括一个实根,事实上我想要的就是那个实根.我用了inline函数把实根找到了,可是想不通为什么这个solve不行,(不要说有定理证明五次以上没解析解……)最重要的是,我想请教一下除了inline把实根找到以外,还可不可以用别的方法啊,最好能显示出七个根那种.谢谢大家啊.
各位大神们,我在用matlab解一个高次方程时出了问题.它只给我返回了一个虚根.clcclearsyms hc1E0=7.1260;q=11;fai=0.9030;g=9.8;A=3.76;f=(hc1+(q^2)/(2*g*(fai^2)*hc1^2))-E0-((1.05*(hc1/2)*(sqrt(1+8*((q^2)/(g*hc1^3)))-1))+(q^2)/(2
你要精确到多少?
{{hc1 -> -3.17846 - 3.71375 I},
{hc1 -> -3.17846 + 3.71375 I},
{hc1 -> -1.0783 - 0.47485 I},
{hc1 -> -1.0783 + 0.47485 I},
{hc1 -> 1.01888},
{hc1 -> 3.41177 - 2.33841 I},
{hc1 -> 3.41177 + 2.33841 I}}