OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′求∠BOD的度数
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![OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′求∠BOD的度数](/uploads/image/z/4030038-54-8.jpg?t=OA%E2%8A%A5OC%E4%BA%8EO%2C%E7%82%B9B%2CO%2CE%E5%9C%A8%E5%90%8C%E4%B8%80%E6%9D%A1%E7%9B%B4%E7%BA%BF%E4%B8%8A%2C%E4%B8%94OD%E5%B9%B3%E5%88%86%E2%88%A0COE%2C%E2%88%A0AOB%3D41%C2%B012%E2%80%B2OA%E2%8A%A5OC%E4%BA%8EO%2C%E7%82%B9B%2CO%2CE%E5%9C%A8%E5%90%8C%E4%B8%80%E6%9D%A1%E7%9B%B4%E7%BA%BF%E4%B8%8A%EF%BC%8C%E4%B8%94OD%E5%B9%B3%E5%88%86%E2%88%A0COE%EF%BC%8C%E2%88%A0AOB%3D41%C2%B012%E2%80%B2%E6%B1%82%E2%88%A0BOD%E7%9A%84%E5%BA%A6%E6%95%B0)
OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′求∠BOD的度数
OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′
OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′求∠BOD的度数
OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′OA⊥OC于O,点B,O,E在同一条直线上,且OD平分∠COE,∠AOB=41°12′求∠BOD的度数
可以画图
∠COE=48°88′
OD平分∠COE
∠COD=∠DOE=24°44′
∠BOD=∠AOB+∠AOC+∠COD
=41°12′+90°+24°44′=155°56′
毕业太多年了,都忘差不多了
题很简单,读题却相当困难
一种情况就是BOE在COA内侧
∠AOB=41°12'
OD平分∠COE
则2∠COE+90°-41°12'=180°
则∠BOD=∠COE/2+90°-41°12'
=135°-20.6°=114.4°=114°24'
另外一种情况就是BOE在COA外侧
∠BOD=180°-45°+41.2°/2...
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题很简单,读题却相当困难
一种情况就是BOE在COA内侧
∠AOB=41°12'
OD平分∠COE
则2∠COE+90°-41°12'=180°
则∠BOD=∠COE/2+90°-41°12'
=135°-20.6°=114.4°=114°24'
另外一种情况就是BOE在COA外侧
∠BOD=180°-45°+41.2°/2
=135°+20.6°=155°36’
收起
(1)当∠COE<90°
∠AOB=41°12′
∠COE=∠COB=90°-∠AOB=90°-41°12′=48°48′
OD平分∠COE
则∠BOD=∠COD=48°48′/2=24°24
(2)当∠COE>90°
∠AOB=41°12′
∠COE=∠COB=90°+∠AOB=90°+41°12′=131°12′
OD平分∠COE
则∠BOD=∠COD=131°12′/2=65°36′