先化简,再求值,[x²+y²-(x-y)²+2y(x-y)]÷4y.其中x,y满足x²-2x+1+|y+1|=0
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先化简,再求值,[x²+y²-(x-y)²+2y(x-y)]÷4y.其中x,y满足x²-2x+1+|y+1|=0
先化简,再求值,[x²+y²-(x-y)²+2y(x-y)]÷4y.其中x,y满足x²-2x+1+|y+1|=0
先化简,再求值,[x²+y²-(x-y)²+2y(x-y)]÷4y.其中x,y满足x²-2x+1+|y+1|=0
[x²+y²-(x-y)²+2y(x-y)]÷4y
=[x²+y²-(x²-2xy+y²)+2y(x-y)]÷4y
=(x²+y²-x²+2xy-y²+2xy-2y²)÷4y
=(4xy-2y²)÷4y
化简得=(2x-y)÷2
x²-2x+1+|y+1|=0
(x-1)²+|y+1|=0
(x-1)²=0 |y+1|=0
x=1 y= -1
所以(2x-y)÷2=3/2