如图,在△ABC中,AD为∠BAC的平分线,AD的垂直平分线EF交BC的延长线于点F,连接AF求证1、∠B=∠CAF2、△ABD∽△CAF3、AF²=FC*EB
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![如图,在△ABC中,AD为∠BAC的平分线,AD的垂直平分线EF交BC的延长线于点F,连接AF求证1、∠B=∠CAF2、△ABD∽△CAF3、AF²=FC*EB](/uploads/image/z/4037774-14-4.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAD%E4%B8%BA%E2%88%A0BAC%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%2CAD%E7%9A%84%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86%E7%BA%BFEF%E4%BA%A4BC%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%8E%E7%82%B9F%2C%E8%BF%9E%E6%8E%A5AF%E6%B1%82%E8%AF%811%E3%80%81%E2%88%A0B%3D%E2%88%A0CAF2%E3%80%81%E2%96%B3ABD%E2%88%BD%E2%96%B3CAF3%E3%80%81AF%26sup2%3B%3DFC%2AEB)
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