函数y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)是偶函数还是奇函数?

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/06 04:30:36
函数y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)是偶函数还是奇函数?
x){ھ Fq ZP3V;'O">i6gK!\{"}_`gC=iTh4T6(DCچ`պpXUez鄞';gj@ A4DP]`Q4lsu9xmuՆHމԈ,k:^ tGaQn U ~Hxn֓O )3@rXYPF 18!d

函数y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)是偶函数还是奇函数?
函数y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)是偶函数还是奇函数?

函数y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)是偶函数还是奇函数?
f(x)=y=[(2^x-1)/(2^x+1)]+ln(x-1)/(x+1)
f(-x)=[2^(-x)-1]/[2^(-x)+1]+ln(-x-1)/(-x+1)
[2^(-x)-1]/[2^(-x)+1]
上下同乘2^x
=(1-2^x)/(1+2^x)
=-(2^x-1)/(2^x+1)
ln(-x-1)/(-x+1)=ln[-(x+1)/-(x-1)]=ln(x+1)/(x-1)=ln{1/[(x-1)/(x+1)]}
=ln[(x-1)/(x+1)]^-1
=-ln(x-1)/(x+1)
所以f(-x)=-(2^x-1)/(2^x+1)-ln(x-1)/(x+1)
=-[(2^x-1)/(2^x+1)+ln(x-1)/(x+1)]
=-f(x)
又定义域
(x-1)/(x+1)>0
所以(x-1)(x+1)>0
x>1,x

函数,y=3x/(x^2+x+1) ,x 函数y=3x/(x^2+x+1) （x 函数y=2x/x²-x+1（x 函数y=2^x+1/2^x-1 (x 函数y=根号1-x/|x+1|+|x+2| 函数y=（x^2-x+1)^x的导数 函数y=2x+3除以(x-1)(x 函数y=(2x+3)/(x-1)(x y=x^2+x/x+1的函数图象 y(x)=(2-x)/(x-1)的函数图象 y/(x-y)=x^2+1 隐函数求导 y=|2x-3|的函数图象,y=x/(x-1)的函数图象 函数值域问题,很简单函数y=3x/(x^2+x+1) (x 函数y=x^2+1（-1 作函数y= x (x>0) 1 (-1≤x≤1) -2x (x 函数Y=2^x/(2^x+1)(-1 求函数y=(x^2+1)/(x-1)(2 y=｜x-1｜+ ｜2x+ 1｜分段函数