已知a²-3a+1=0,求a+a/1和a²+1/a²的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/10 11:49:46
![已知a²-3a+1=0,求a+a/1和a²+1/a²的值](/uploads/image/z/4075839-63-9.jpg?t=%E5%B7%B2%E7%9F%A5a%26%23178%3B%EF%BC%8D3a%EF%BC%8B1%EF%BC%9D0%2C%E6%B1%82a%2Ba%2F1%E5%92%8Ca%26%23178%3B%EF%BC%8B1%2Fa%26%23178%3B%E7%9A%84%E5%80%BC)
x){}KՔ
-5N|:66%j'>6ԇjyڰ&Hb3lqXFA&)hyԹ@GɎ%/|:%Ov/M|o= *@Z i5!"om,tv̄HjA&$Á65N뇸Hc>ڹٴȁm
E!n
已知a²-3a+1=0,求a+a/1和a²+1/a²的值
已知a²-3a+1=0,求a+a/1和a²+1/a²的值
已知a²-3a+1=0,求a+a/1和a²+1/a²的值
a² - 3a + 1 = 0
a² + 1 = 3a
a≠0, 两边同除以a得:
a + 1/a = 3 .
(a + 1/a )²= a² + 2 + 1/a² = 9 ,则
a² + 1/a² = 7 .
a²+1=3a
两边除以a
a+1/a=3
a+1/a=3
两边平方
a²+2+1/a²=9
a²+1/a²=7