log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=
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log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=
log3^2*log5^7/log9^1/7*log125^8
2.log2^3=1-a/a,则log3^12=
log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=
2log3*7log5/(2/7)log3*24log5=49/24
log9^1/7*log125^8=(1/2)log3^1/7*(1/3*3)log5^2=(1/2)log3^1/7*log5^2
∴log3^2*log5^7/ log9^1/7*log125^8=49/24
log3^2*log5^7/log9^1/7*log125^82.log2^3=1-a/a,则log3^12=
化简:log2 2+log5 1-3^(2log9 5)+(3log3 5)^2+3^log3 2
log5[log2(log9/log3)]=?
-5log9 4+log3 32/9-5^log5 3-(1/64)^-2/3
计算:-5log9^4+log3^32/9-5log5^3-(1/64)^-2/3
5log9 4 + log3 32/9 - 5的log5 3次方 - (1/64)的-2/3次方
(log4 3+log8 3)(log3 5+log9 5)(log5 2+log25 2)=
log3*2/log9*4
log3 5-log3 15+1/2log9 27 的值
-5log9为底4的对数+log3为底(32/9)的对数-5^(log5为底3的对数)-(1/64)^(-2/3)
log5·log5(3)·log5(1/3)log3(5)·log5(3)·log5(1/3)log3(2)·log5(3)·log8(5)不好意思
log3*2/log9*4=?
(log2^3 +log3^5) x ( log3^5 +log9^5 ) x lg 2 ,本人对数特别差,最好带解说,(log2^3 +log5^3) x ( log3^5 +log9^5 ) x lg 2
化简log2[log3(log5 125)]……1.化简log2[log3(log5 125)]2.5log2(log9 81)3.log9 4 +log3 8 /log1/3 164.求值(lg2)^2+两个2*lg5+lg503.log9 4 +log3 8除以log三分之一 16 4.求值(lg2)平方+lg2乘以lg5+lg50
利用换底公式求值:1.log2 25 ×log3 4 ×log5 9 2.(log4 3+log8 3)(log3 2+log9 2)
|log3(5)-2|+log9(25)+(1/32)^1/5
1、计算log5^35+2log1/2^根号2-log5^1/50-log5^14 2、已知log3^7=a,log2^3=b,求log21^28
1/log5^7+1/log3^7+1/log2^7 ,求值