若ab=2,a+b=5,(a+b)²=a²+2ab²+b²+1=?
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若ab=2,a+b=5,(a+b)²=a²+2ab²+b²+1=?
若ab=2,a+b=5,(a+b)²=a²+2ab²+b²+1=?
若ab=2,a+b=5,(a+b)²=a²+2ab²+b²+1=?
∵ab=2
∴2ab²=2x2²=8
∵a+b=5
∴a²+b²=5²=25
∴a²+2ab²+b²+1= 8+25+1 =34