2道一元二次方程数学题,6x²-40=0x（3x-1）=3-x

2道一元二次方程数学题,6x²-40=0x（3x-1）=3-x
2道一元二次方程数学题,
6x²-40=0
x（3x-1）=3-x

2道一元二次方程数学题,6x²-40=0x（3x-1）=3-x
1,x=正负3分之 "2根号15"
2,x=正负一

6 x ² - 40 = 0
2（3 x ² - 20）= 0
3 x ² - 20 = 0
x（3 x - 20）= 0
x = 0 或 3 x - 20 = 0
x1 = 0 3 x2 = 20
...

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6 x ² - 40 = 0
2（3 x ² - 20）= 0
3 x ² - 20 = 0
x（3 x - 20）= 0
x = 0 或 3 x - 20 = 0
x1 = 0 3 x2 = 20
x2 = 20 / 3


x（3 x - 1）= 3 - x
x（3 x - 1）- 3 + x = 0
3 x ² - x - 3 + x = 0
3 x ² - 3 = 0
3（x ² - 1）= 0
x ² - 1 = 0
x ² = 1
x = ± 1

x1 = 1

x2 = - 1

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