解一元二次方程:x²-4ax=b²-4ax²-4ax=b²-4a²x²-4ax+4a²-b²=0(x²-4ax+4a²)-b²=0(x-2a)²-b²=0[(x-2a)+b][(x-2a)-b]=0(x-2a+b)(x-2a-b)=0[x-(2a-b)][x-(2a+b)]=0x1=2a-b,x2=2a+b
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![解一元二次方程:x²-4ax=b²-4ax²-4ax=b²-4a²x²-4ax+4a²-b²=0(x²-4ax+4a²)-b²=0(x-2a)²-b²=0[(x-2a)+b][(x-2a)-b]=0(x-2a+b)(x-2a-b)=0[x-(2a-b)][x-(2a+b)]=0x1=2a-b,x2=2a+b](/uploads/image/z/4109619-3-9.jpg?t=%E8%A7%A3%E4%B8%80%E5%85%83%E4%BA%8C%E6%AC%A1%E6%96%B9%E7%A8%8B%EF%BC%9Ax%26%23178%3B-4ax%3Db%26%23178%3B-4ax%26%23178%3B-4ax%3Db%26%23178%3B-4a%26%23178%3Bx%26%23178%3B-4ax%2B4a%26%23178%3B-b%26%23178%3B%3D0%28x%26%23178%3B-4ax%2B4a%26%23178%3B%29-b%26%23178%3B%3D0%28x-2a%29%26%23178%3B-b%26%23178%3B%3D0%5B%28x-2a%29%2Bb%5D%5B%28x-2a%29-b%5D%3D0%28x-2a%2Bb%29%28x-2a-b%29%3D0%5Bx-%282a-b%29%5D%5Bx-%282a%2Bb%29%5D%3D0x1%3D2a-b%EF%BC%8Cx2%3D2a%2Bb)
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