若方程组﹛a₁x+b₁y=c₁ 的解是﹛x=3 ,则方程组﹛a₁(x-1)+b₁(y+1)=c₁ 的解是____________ ﹛a₂x+b₂y=c₂ ﹛y=4 ﹛a₂ (x-1)+b₂(y+1)=c₂
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若方程组﹛a₁x+b₁y=c₁ 的解是﹛x=3 ,则方程组﹛a₁(x-1)+b₁(y+1)=c₁ 的解是____________ ﹛a₂x+b₂y=c₂ ﹛y=4 ﹛a₂ (x-1)+b₂(y+1)=c₂
若方程组﹛a₁x+b₁y=c₁ 的解是﹛x=3 ,则方程组﹛a₁(x-1)+b₁(y+1)=c₁ 的解是____________
﹛a₂x+b₂y=c₂ ﹛y=4 ﹛a₂ (x-1)+b₂(y+1)=c₂
若方程组﹛a₁x+b₁y=c₁ 的解是﹛x=3 ,则方程组﹛a₁(x-1)+b₁(y+1)=c₁ 的解是____________ ﹛a₂x+b₂y=c₂ ﹛y=4 ﹛a₂ (x-1)+b₂(y+1)=c₂
由前方程得3(a1-a2)+4(b1-b2)=c1-c2,把C1-C2带入后方程组得:(a1-a2)x+(b1-b2)y-(a1-a2)+(b1-b2)=3(a1-a2)+4(b1-b2).所以(a1-a2)x+(b1-b2)y=4(a1-a2)+3(b1-b2).所以x=4,y=3