设函数f(x)=2sin(2x-3π/4)+1,求函数y=f(x)单调增区间

设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f (x)=cos(2x-π/3)-2sin平方x (1)求函数f(x 设函数f(x)=sin(3x)+|sin(3x)|,函数的最小正周期为什么是2π? 设函数f(x)=sin(πx/2+π/4)x 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sin(wx+t)(-π/2 设函数f(x)=sinπ/6（x),则f(1)+f(2)+f(3)+…f(2008)=?