一道SAT概率题求解TOT 之前有人问过,可是过程没看明白.能否详细点= =A,B,C,D ,E ,F,Ga list consists of all possible three-letter arrangements formed by using the letters above such that the first letter is D and one of the remain

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一道SAT概率题求解TOT 之前有人问过,可是过程没看明白.能否详细点= =A,B,C,D ,E ,F,Ga list consists of all possible three-letter arrangements formed by using the letters above such that the first letter is D and one of the remain
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一道SAT概率题求解TOT 之前有人问过,可是过程没看明白.能否详细点= =A,B,C,D ,E ,F,Ga list consists of all possible three-letter arrangements formed by using the letters above such that the first letter is D and one of the remain
一道SAT概率题求解TOT 之前有人问过,可是过程没看明白.能否详细点= =
A,B,C,D ,E ,F,G
a list consists of all possible three-letter arrangements formed by using the letters above such that the first letter is D and one of the remaining letters is A.if no letter is used more than once in an arrangement in the list and one three-letter arrangement is randomly selected from the list,what is the probability that the arrangement selected will be DCA?

一道SAT概率题求解TOT 之前有人问过,可是过程没看明白.能否详细点= =A,B,C,D ,E ,F,Ga list consists of all possible three-letter arrangements formed by using the letters above such that the first letter is D and one of the remain
一共是three-letter,第一个已经确定是D,又说three-letter有A.所以A在第3个的概率是1/2.从剩下5个字母中选C的概率是1/5..1/2 * 1/5= 1/10

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