x=acos³x y=asin³t 求d²y/dx²
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/11 10:38:48
![x=acos³x y=asin³t 求d²y/dx²](/uploads/image/z/4316035-67-5.jpg?t=x%3Dacos%26%23179%3Bx+y%3Dasin%26%23179%3Bt+%E6%B1%82d%26%23178%3By%2Fdx%26%23178%3B)
x)ML/VS64PM,̃JmlJ-+S* ,"}5ِi3X
Ϧ|=̂EVdR 8 X$b\mJJu[ct1(LըPTWT4J^uO$ACyڱO{ymO;V?ЉT J?m|gvl Io4OvOv<[zقH ̷
x=acos³x y=asin³t 求d²y/dx²
x=acos³x y=asin³t 求d²y/dx²
x=acos³x y=asin³t 求d²y/dx²
这是参数方程求导:
x'=-3asintcos^2t
x''=-3acos^3t+6asin^2tcost
y'=3asin^2tcost
x''=-3asin^3t+6asintcos^2t
d²y/dx²=(x'y''-x''y')/(x')^3
代入即可.
利用反函数的求导公式,分别把X,Y 的关系找到,就可以了,二次导也是一样