x+y+z=2y=3z(y≠0),求(xy+yz+zx)÷(x²+y²+z²)的值.

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x+y+z=2y=3z(y≠0),求(xy+yz+zx)÷(x²+y²+z²)的值.
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x+y+z=2y=3z(y≠0),求(xy+yz+zx)÷(x²+y²+z²)的值.
x+y+z=2y=3z(y≠0),求(xy+yz+zx)÷(x²+y²+z²)的值.

x+y+z=2y=3z(y≠0),求(xy+yz+zx)÷(x²+y²+z²)的值.
令x+y+z=2y=3z=6k
y = 3k
z = 2k
x = k
(xy+yz+zx)÷(x²+y²+z²)
=(3k²+6k²+2k²)÷(k²+9k²+4k²)
=(11k²)÷(14k²)
=11/14

等于14