(x+y)^2-x^2y^2.x^2-3x-1

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(x+y)^2-x^2y^2.x^2-3x-1
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(x+y)^2-x^2y^2.x^2-3x-1
(x+y)^2-x^2y^2.x^2-3x-1

(x+y)^2-x^2y^2.x^2-3x-1
(1) 原式=(x+y-xy)(x+y+xy)
(2) 原式=[x-(√13+3)/2][x+(√13+3)/2]

(x+y)^2-x^2y^2
=(x+y)²-(xy)²
=[(x+y)+xy][(x+y)-xy]
=(x+y+xy)(x+y-xy)

x^2-3x-1
=x²-3x+9/4 -13/4
=(x-3/2)²-13/4
=(x-3/2+√13/2)(x-3/2-√13/2)