已知实数x满足(x²-x﹚²-4﹙x²-x﹚-12=0,则代数式x²-x+1的值为?
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已知实数x满足(x²-x﹚²-4﹙x²-x﹚-12=0,则代数式x²-x+1的值为?
已知实数x满足(x²-x﹚²-4﹙x²-x﹚-12=0,则代数式x²-x+1的值为?
已知实数x满足(x²-x﹚²-4﹙x²-x﹚-12=0,则代数式x²-x+1的值为?
(x²-x﹚²-4﹙x²-x﹚-12=0
(x²-x+2﹚×﹙x²-x-6﹚=0
∵ x²-x+2=(x- 1/2)²+ 5/4>0
∴ x²-x-6=0
即x²-x=6
x²-x+1=6+1=7