已知|3-y|+|x+y|=0,求[2(x+y)-3(xy+4)]÷1/xy的值.
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已知|3-y|+|x+y|=0,求[2(x+y)-3(xy+4)]÷1/xy的值.
已知|3-y|+|x+y|=0,求[2(x+y)-3(xy+4)]÷1/xy的值.
已知|3-y|+|x+y|=0,求[2(x+y)-3(xy+4)]÷1/xy的值.
3-y=0
x+y=0
∴x=-3
y=3
[2(x+y)-3(xy+4)]÷1/xy
=[2×0-3(-9+4)]÷(-1/9)
=15×(-9)
=-135
|3-y|+|x+y|=0
所以
3-y=0,x+y=0
所以y=3.x=-3
所以xy=-9
所以原式=[2*0-3*(-9+4)]÷(-1/9)
=135
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