设函数f(x,y)= xy^2/(x^2+y^4); (x,y)不等于(0,0) 0 ; (x,y)=(0,0) 判断f(x,y)在点(0,0)处的极限与连续性就是这个函数分为(x,y)等于0和不等于0两种情况,一个得到函数式,一个得到0.我只知道设x=ky^2,然后代入
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![设函数f(x,y)= xy^2/(x^2+y^4); (x,y)不等于(0,0) 0 ; (x,y)=(0,0) 判断f(x,y)在点(0,0)处的极限与连续性就是这个函数分为(x,y)等于0和不等于0两种情况,一个得到函数式,一个得到0.我只知道设x=ky^2,然后代入](/uploads/image/z/4327335-63-5.jpg?t=%E8%AE%BE%E5%87%BD%E6%95%B0f%28x%2Cy%29%3D+xy%5E2%2F%28x%5E2%2By%5E4%29%3B+%28x%2Cy%29%E4%B8%8D%E7%AD%89%E4%BA%8E%280%2C0%29+0+%3B+%28x%2Cy%29%3D%280%2C0%29+%E5%88%A4%E6%96%ADf%28x%2Cy%29%E5%9C%A8%E7%82%B9%280%2C0%29%E5%A4%84%E7%9A%84%E6%9E%81%E9%99%90%E4%B8%8E%E8%BF%9E%E7%BB%AD%E6%80%A7%E5%B0%B1%E6%98%AF%E8%BF%99%E4%B8%AA%E5%87%BD%E6%95%B0%E5%88%86%E4%B8%BA%28x%2Cy%29%E7%AD%89%E4%BA%8E0%E5%92%8C%E4%B8%8D%E7%AD%89%E4%BA%8E0%E4%B8%A4%E7%A7%8D%E6%83%85%E5%86%B5%2C%E4%B8%80%E4%B8%AA%E5%BE%97%E5%88%B0%E5%87%BD%E6%95%B0%E5%BC%8F%2C%E4%B8%80%E4%B8%AA%E5%BE%97%E5%88%B00.%E6%88%91%E5%8F%AA%E7%9F%A5%E9%81%93%E8%AE%BEx%3Dky%5E2%2C%E7%84%B6%E5%90%8E%E4%BB%A3%E5%85%A5)
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