如图,在三角形ABC中,已知角ACB=90度,CD为AB边上的高,DE垂直AC于点E,三角形ADE的中线AG的延长线交BC于点F(1)若CF=FG,求证:FG=1/3AF (2)在(2)的条件下,若AC=6倍根号2,求DE的长
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![如图,在三角形ABC中,已知角ACB=90度,CD为AB边上的高,DE垂直AC于点E,三角形ADE的中线AG的延长线交BC于点F(1)若CF=FG,求证:FG=1/3AF (2)在(2)的条件下,若AC=6倍根号2,求DE的长](/uploads/image/z/4327757-53-7.jpg?t=%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E4%B8%AD%2C%E5%B7%B2%E7%9F%A5%E8%A7%92ACB%3D90%E5%BA%A6%2CCD%E4%B8%BAAB%E8%BE%B9%E4%B8%8A%E7%9A%84%E9%AB%98%2CDE%E5%9E%82%E7%9B%B4AC%E4%BA%8E%E7%82%B9E%2C%E4%B8%89%E8%A7%92%E5%BD%A2ADE%E7%9A%84%E4%B8%AD%E7%BA%BFAG%E7%9A%84%E5%BB%B6%E9%95%BF%E7%BA%BF%E4%BA%A4BC%E4%BA%8E%E7%82%B9F%281%29%E8%8B%A5CF%3DFG%2C%E6%B1%82%E8%AF%81%EF%BC%9AFG%3D1%2F3AF++%282%29%E5%9C%A8%EF%BC%882%EF%BC%89%E7%9A%84%E6%9D%A1%E4%BB%B6%E4%B8%8B%2C%E8%8B%A5AC%3D6%E5%80%8D%E6%A0%B9%E5%8F%B72%2C%E6%B1%82DE%E7%9A%84%E9%95%BF)
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